Late to the party but here's a solution I worked out using roots of unity and co...

		susam 45 days ago \| parent \| context \| favorite \| on: Fizz Buzz without conditionals or booleans Late to the party but here's a solution I worked out using roots of unity and cosines: `from math import cos, pi for n in range(1, 101): print([n, 'Fizz', 'Buzz', 'FizzBuzz'][round((1 + 2 * cos(2 * pi * n / 3)) / 3 + 2 * (1 + 2 * cos(2 * pi * n / 5) + 2 * cos(4 * pi * n / 5)) / 5)])`

As it should be.